Lab and field counts · Ecology
Mark and recapture: estimating a population with Lincoln-Petersen and Chapman, and why a few recaptures are not enough

The tool for this guide: Open the multi counter
Mark M animals and release them; later catch C, of which R carry marks. The Lincoln-Petersen estimate is N = M × C ÷ R. Chapman's version, N = (M + 1)(C + 1) ÷ (R + 1) − 1, removes most of the small-sample bias and is the one to report. With fewer than about ten recaptures, the 95% interval runs from roughly half to nearly double the estimate.
How the Lincoln-Petersen estimate works
Mark a known number of animals, let them mix back in, catch a second sample, and assume the share of marked animals in that sample equals their share in the whole population. If 200 marked beetles are mixed into a population and 12 of the next 150 caught are marked, then 200 is to N as 12 is to 150, so N = 200 × 150 ÷ 12 = 2,500.
| Count | Krebs and Ricker | Common in revision notes |
|---|---|---|
| Marked and released in the first sample | M | n₁ |
| Caught in the second sample, marked or not | C | n₂ |
| Of those, already marked | R | m₂ |
| Population estimate | N̂ = M × C ÷ R | N = n₁ × n₂ ÷ m₂ |
The idea is older than ecology. W. E. Ricker's handbook for Canada's Fisheries Research Board, Computation and Interpretation of Biological Statistics of Fish Populations (Bulletin 191, 1975), traces it to John Graunt's Observations on the London Bills of Mortality of 1662, in which children born in a year were the "marked" individuals. C. G. J. Petersen applied it to marked fish from 1896; Knut Dahl used it for trout in Norwegian tarns about ten years later; and Lincoln brought it to birds in 1930, estimating duck numbers from band returns. Hence the two names on one formula.
The Chapman estimator, and why it is the one to report
Chapman's estimator, N = (M + 1)(C + 1) ÷ (R + 1) − 1, corrects the plain formula's tendency to overestimate, and is the version to use unless recaptures are in the hundreds. Ricker reports that Bailey (1951) and Chapman (1951) showed the simple estimate "tends to overestimate the true population", and that Chapman's version gives "an unbiased estimate in most situations". In Charles Krebs's Ecological Methodology, chapter 2 (University of British Columbia, draft third edition), the same formula is the one Seber (1982) recommends: unbiased if M + C is greater than N, and nearly unbiased with at least seven recaptures.
Three details trip people up:
- The −1. Krebs keeps it; Ricker drops it as "of no practical significance". Either way the answer rounds to the same estimate, but say which you used when you compare with someone else.
- No recaptures. With R = 0, Lincoln-Petersen divides by zero. Chapman still returns a number, but it only says the samples were too small.
- Sightings instead of captures. If the second sample is a count of sightings, so one animal can be counted twice, Krebs gives Bailey's version, N = M(C + 1) ÷ (R + 1), which assumes marked and unmarked animals are equally likely to be seen.
| Example | M | C | R | Lincoln-Petersen | Chapman |
|---|---|---|---|---|---|
| Small sample | 40 | 40 | 4 | 400 | 335 |
| Beetles, below | 200 | 150 | 12 | 2,500 | 2,334 |
| Trout, Dahl (Ricker 1975) | 109 | 177 | 57 | 338 | 337 |
| Snowshoe hares (Krebs, Box 2.1) | 948 | 421 | 167 | 2,390 | 2,383 |
The gap between the two shrinks as R grows: 16% at four recaptures, under 1% at 167. Ricker reports the trout as 337 from 110 × 178 ÷ 58 = 337.6, without the −1; with it, 336.6 rounds to 337.
Worked example: ground beetles in a field margin
A survey marks ground beetles caught in pitfall traps along a field margin with a dot of paint and releases them. A week later the traps are run again with the same effort. The numbers are made up for the example; the method is Krebs's and Ricker's.
- First sample. 200 beetles marked and released: M = 200.
- Second sample. 150 caught: C = 150. Of these, 12 carry paint: R = 12.
- Lincoln-Petersen. 200 × 150 ÷ 12 = 2,500.
- Chapman. 201 × 151 ÷ 13 − 1 = 30,351 ÷ 13 − 1 = 2,334.7 − 1 = 2,334.
- Choose the interval. R ÷ C = 12 ÷ 150 = 0.08, below 0.10, and R is under 50, so Seber's guide says Poisson limits (see the next section).
- Limits for R. Krebs's Table 2.1 gives 95% Poisson limits of 6.686 and 20.335 for 12.
- Put each limit in place of R. 30,351 ÷ 21.335 − 1 = 1,422 and 30,351 ÷ 7.686 − 1 = 3,948.
- Report it. About 2,300 beetles, 95% confidence interval 1,400 to 3,900.
Two checks follow. The bias condition in Ricker, M × C greater than four times N, holds: 200 × 150 = 30,000, more than four times 2,334. And the interval is wide: the true number could be about 60% of the estimate or two thirds above it, because 12 recaptures is a small count.
Which confidence interval to use
Put confidence limits on the number of recaptures, then convert each limit into a population size; which limits to use depends on how large R is and how large a share of the second sample it makes. Krebs sets out Seber's decision guide:
| Your data | Interval to use | Krebs's worked example |
|---|---|---|
| R ÷ C above 0.10 | Binomial limits for R ÷ C, best by the Wilson method | 50 birds marked, 22 caught, 14 marked: 0.430 to 0.803, so N from 62 to 116 |
| R ÷ C at most 0.10 and R above 50 | Normal approximation for R ÷ C | 1,800 marked, 800 caught, 73 marked: N from 16,154 to 25,326 |
| R ÷ C at most 0.10 and R 50 or fewer | Poisson limits for R, from a table | 600 marked, 200 caught, 13 marked: N from 5,402 to 15,716 |
For the binomial case, the limits apply to the marked share. Krebs's bird example converts them as N = M ÷ (R ÷ C): with the Wilson limits, 50 ÷ 0.803 = 62 and 50 ÷ 0.430 = 116. The snowshoe hare data in his Box 2.1, from Green and Evans's live-trapping in Minnesota in the winter of 1932-33, have R ÷ C = 0.397, so they too take binomial limits, by the Wilson method: 2,383 hares, 95% interval 2,135 to 2,700. Ricker's Example 3.1 does the same for Dahl's trout, 337 with limits of 272 and 417.
Note the shape of every interval: it reaches further above the estimate than below. Because N depends on 1 ÷ R, a recapture count that is low by chance raises the estimate more than a count high by the same amount lowers it. An estimate written as "2,334 ± 1,000" misstates that.
Why a few recaptures are not enough
Below about ten recaptures the estimate is too imprecise to be much use, even when it is not biased: with four recaptures the 95% range runs from about half to about double. Two separate problems meet here, and the sources give a threshold for each:
- Bias. Ricker says the probability of the zero-recapture kind of bias "can be ignored if recaptures number 3-4 or more". Seber, as Krebs reports him, calls Chapman's estimate nearly unbiased from seven recaptures.
- Precision. The interval depends on how many recaptures you have, and it narrows slowly, as the table shows.
| Recaptures (R) | Poisson limits for R | Range for the true population |
|---|---|---|
| 2 | 0.355 to 6.686 | 0.39 to 2.21 times the estimate |
| 4 | 1.366 to 9.598 | 0.47 to 2.11 times |
| 7 | 3.285 to 13.765 | 0.54 to 1.87 times |
| 10 | 5.323 to 17.633 | 0.59 to 1.74 times |
| 20 | 12.817 to 30.017 | 0.68 to 1.52 times |
| 30 | 20.33 to 41.75 | 0.73 to 1.45 times |
| 50 | 37.67 to 64.95 | 0.77 to 1.32 times |
The limits are Krebs's Table 2.1, from Crow and Gardner (1959); each multiple is (R + 1) divided by (limit + 1). This is why Robson and Regier's charts, which Ricker reproduces, call for roughly 25 to 75 recaptures to land within ±25% of the true population 19 times in 20, depending on how large the population is.
Planning: how many to mark and how many to catch
Decide the accuracy you need, guess the population on the high side, and choose M and C so the expected number of recaptures, M × C ÷ N, is large enough. Krebs passes on Robson and Regier's three standard levels, each 95% of the time: ±50% for a preliminary survey, ±25% for management and ±10% for research.
A worked plan: you expect about 2,000 animals and want management accuracy, so aim for at least 25 recaptures. M × C ÷ 2,000 = 25 means M × C = 50,000, for example 225 marked and 225 caught. Krebs notes that keeping M and C about equal handles the fewest animals for a given precision, and that "it is often necessary to mark 50% or more of the individuals in a population" for even moderate accuracy. If 450 handlings is beyond the project, the honest choice is a preliminary-survey accuracy, or a different method, not a confident number from ten recaptures.
Ricker's simpler check for bias, M × C greater than four times N, is a floor, not a target: for 2,000 animals it needs only 8,000, such as 90 × 90, which would give about four recaptures.
The five assumptions, and what breaking each does
The estimate is only as good as five assumptions, which Krebs lists for the Petersen method; most failures push the estimate up. The direction follows from N = M × C ÷ R: anything that lowers the marked share of the second sample inflates N, and anything that raises it deflates N.
| Assumption (Krebs) | Common way it fails | Effect on the estimate |
|---|---|---|
| 1. The population is closed | Young animals join, or animals move in, between samples | Too high (Krebs: recruitment inflates N) |
| 2. Every animal is equally likely to be caught in the first sample | Some animals are never near the traps | The estimate covers only the catchable population |
| 3. Marking does not affect catchability | Marked animals learn to avoid traps, or come back for the bait | Avoiding: too high. Returning: too low |
| 4. Marks are not lost | Paint wears off, tags fall out | Too high |
| 5. All marks are noticed and recorded | A faint mark is missed in the second sample | Too high |
Krebs adds that deaths during marking leave the estimate valid for the population after release, that N always means the catchable population (nets miss small fish), and that the best defence against recruitment is to take both samples over a short period. Random sampling is the other half: he advises dividing the area into equal subareas and sampling randomly chosen ones with the same effort, rather than relying on marked animals mixing evenly.
Lost marks can be measured. Krebs's example marks 500 beetles with two kinds of paint and finds, in the second sample, 23 with only the first mark, 6 with only the second and 127 with both. His formula estimates 157 recaptures against the 156 seen: one beetle lost both marks.
Counting marked and unmarked in the field
Record M exactly when you release, and in the second sample count marked and unmarked animals as two separate tallies; C is their sum. Counting only the marked ones and estimating the total afterwards is how C goes wrong.
Simple Online Counter is a free, browser-based set of counters that keeps its counts in your browser's own storage. In the multi counter, name two counters "marked" and "unmarked" and tap one per animal as you check it; add a third for animals that died in the trap if you need to subtract them. The tally counter does the first sample with one tap per animal marked. The yes/no counter shows the marked share of the second sample as you go, with a normal-approximation range once you pass 30 animals; for small numbers of recaptures use the Poisson or binomial limits above instead. None of these marks or identifies animals: the counts are yours, and the formulas turn them into an estimate. Round the result to the precision the interval supports, as the flock counting guide argues for any estimate.
Beyond two samples: Schnabel and open populations
With more than two capture sessions, the Schnabel method pools them: N = Σ(Cₜ × Mₜ) ÷ ΣRₜ, where each session t catches Cₜ, finds Rₜ already marked, and Mₜ animals carried marks beforehand. Krebs describes it as a weighted average of Petersen estimates, from Schnabel (1938), with every unmarked animal marked and released at each session. When fewer than a tenth of the population is caught or marked per session, he gives a better form with ΣRₜ + 1 below the line.
If the study runs long enough for births, deaths and movement, the population is open and the Petersen family no longer applies. Krebs covers the Cormack-Jolly-Seber method for that case, and programs such as MARK and CAPTURE for designs that test whether catchability varies.
Mistakes the worked examples repeat
| Slip | Fix |
|---|---|
| Arithmetic in the Chapman example is wrong (one published guide gives about 793 for 100, 120, 15) | (101 × 121) ÷ 16 − 1 = 762.8: recompute every example |
| Using Lincoln-Petersen with a handful of recaptures | Use Chapman, and report the interval |
| Giving the interval as ± a single number | The interval is lopsided: give both limits |
| Using a normal-approximation interval for R under 50 | Poisson or binomial limits, by Seber's guide |
| Taking the second sample after weeks of breeding | Keep both samples close together so the population stays closed |
| Planning the numbers after the fieldwork | Choose M and C beforehand from the expected recaptures |
| Using the method on plants or other fixed organisms | Count them in quadrats or in full |
What this guide does not cover
This guide covers the two-sample Petersen family of estimates for closed populations: Lincoln-Petersen, Chapman and Bailey, their confidence intervals, sample sizes and assumptions. It mentions, but does not teach, the Schnabel method, open-population models such as Cormack-Jolly-Seber, and likelihood methods in programs such as MARK, which a study with several sessions or uncertain catchability should use. It does not cover how to capture, mark or handle animals: that depends on the species, and in many countries on permits and animal welfare rules, which your institution or wildlife authority sets.
On the sources: Krebs's chapter is the author's own draft of the third edition, posted by the University of British Columbia; Ricker's Bulletin 191 is the 1975 edition held by Fisheries and Oceans Canada. The figures quoted from Seber, Chapman, Robson and Regier and Crow and Gardner are as those two sources report them.
Frequently asked questions
What is the Lincoln-Petersen formula?
N = M × C ÷ R, where M is the number marked and released in the first sample, C the number caught in the second sample and R the number of those already marked. It assumes the marked share of the second sample equals the marked share of the population. Mark 200, catch 150 with 12 marked, and the estimate is 200 × 150 ÷ 12 = 2,500.
What is the Chapman estimator?
A corrected Lincoln-Petersen estimate: N = (M + 1)(C + 1) ÷ (R + 1) − 1. Chapman and Bailey showed in 1951 that the plain formula tends to overestimate. Chapman's version is unbiased when the two samples together exceed the population, and nearly unbiased with seven or more recaptures. It also gives an answer when no marked animals are recaptured.
Why is Chapman's estimate lower than Lincoln-Petersen?
Because adding one to the recaptures raises the bottom of the fraction proportionally more than adding one to M and C raises the top, when R is small. With 200 marked, 150 caught and 12 recaptured, Lincoln-Petersen gives 2,500 and Chapman 2,334. With 100 or more recaptures the two differ by about 1% or less, so the correction matters most when recaptures are few.
How many recaptures do you need for a reliable estimate?
At least seven for the estimate to be nearly unbiased, and 25 or more for it to land within about ±25% of the truth 19 times in 20, from Robson and Regier's 1964 charts as Ricker reports them. With four recaptures the 95% interval runs from about half the estimate to about double it. Plan the sample sizes before marking anything.
How do you calculate a confidence interval for mark and recapture?
Find confidence limits for the number of recaptures R, then put each limit into the estimator in place of R. Seber's guide: if R ÷ C is above 0.10, use binomial limits; otherwise, use the normal approximation when R exceeds 50 and Poisson limits below that. For 12 recaptures the Poisson limits are 6.686 and 20.335.
What are the assumptions of mark and recapture?
The population is closed, with no births, deaths or movement in or out between samples; every animal has the same chance of capture; marking does not change that chance; marks are not lost; and every mark is noticed and recorded. Breaking any of them biases the estimate, usually upwards when animals are added, marks are lost or marked animals avoid traps.
What happens if no marked animals are recaptured?
The Lincoln-Petersen formula divides by zero and gives no estimate. Chapman's version still gives one, (M + 1)(C + 1) − 1, but it is only a rough lower guide: zero recaptures means the samples were far too small for the population. Ricker's 1975 handbook notes the risk of this bias can be ignored once recaptures number three or four.
Is mark and recapture used for plants?
Rarely, because plants do not move and can be counted where they grow. Fixed organisms are usually estimated with quadrats or a full count. Mark and recapture is for animals that move around and cannot all be seen at once: fish in a lake, small mammals, beetles, butterflies, newts and birds.
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